-4x^2-x=-18

Solution for -4x^2-x=-18 equation:

-4x^2-x=-18

We move all terms to the left:

-4x^2-x-(-18)=0

We add all the numbers together, and all the variables

-4x^2-1x+18=0

a = -4; b = -1; c = +18;
Δ = b2-4ac
Δ = -12-4·(-4)·18
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*-4}=\frac{18}{-8}
=-2+1/4
$